Optimal. Leaf size=274 \[ \frac {1}{2} a^2 \left (12 A b^2+8 a b B+a^2 (A+2 C)\right ) x+\frac {b \left (12 a^2 b B+b^3 B+8 a^3 C+4 a b^2 (2 A+C)\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {(2 A b+a B) (a+b \sec (c+d x))^3 \sin (c+d x)}{d}+\frac {A \cos (c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{2 d}-\frac {b \left (12 a^3 B-24 a b^2 B+a^2 b (39 A-34 C)-2 b^3 (3 A+2 C)\right ) \tan (c+d x)}{6 d}-\frac {b^2 \left (6 a^2 B-3 b^2 B+2 a b (9 A-4 C)\right ) \sec (c+d x) \tan (c+d x)}{6 d}-\frac {b (15 A b+6 a B-2 b C) (a+b \sec (c+d x))^2 \tan (c+d x)}{6 d} \]
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Rubi [A]
time = 0.48, antiderivative size = 274, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 6, integrand size = 41, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.146, Rules used = {4179, 4141,
4133, 3855, 3852, 8} \begin {gather*} -\frac {b^2 \tan (c+d x) \sec (c+d x) \left (6 a^2 B+2 a b (9 A-4 C)-3 b^2 B\right )}{6 d}+\frac {1}{2} a^2 x \left (a^2 (A+2 C)+8 a b B+12 A b^2\right )-\frac {b \tan (c+d x) \left (12 a^3 B+a^2 b (39 A-34 C)-24 a b^2 B-2 b^3 (3 A+2 C)\right )}{6 d}+\frac {b \left (8 a^3 C+12 a^2 b B+4 a b^2 (2 A+C)+b^3 B\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}-\frac {b \tan (c+d x) (6 a B+15 A b-2 b C) (a+b \sec (c+d x))^2}{6 d}+\frac {(a B+2 A b) \sin (c+d x) (a+b \sec (c+d x))^3}{d}+\frac {A \sin (c+d x) \cos (c+d x) (a+b \sec (c+d x))^4}{2 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 3852
Rule 3855
Rule 4133
Rule 4141
Rule 4179
Rubi steps
\begin {align*} \int \cos ^2(c+d x) (a+b \sec (c+d x))^4 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\frac {A \cos (c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{2 d}+\frac {1}{2} \int \cos (c+d x) (a+b \sec (c+d x))^3 \left (2 (2 A b+a B)+(2 b B+a (A+2 C)) \sec (c+d x)-b (3 A-2 C) \sec ^2(c+d x)\right ) \, dx\\ &=\frac {(2 A b+a B) (a+b \sec (c+d x))^3 \sin (c+d x)}{d}+\frac {A \cos (c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{2 d}+\frac {1}{2} \int (a+b \sec (c+d x))^2 \left (12 A b^2+8 a b B+a^2 (A+2 C)-2 b (a A-b B-2 a C) \sec (c+d x)-b (15 A b+6 a B-2 b C) \sec ^2(c+d x)\right ) \, dx\\ &=\frac {(2 A b+a B) (a+b \sec (c+d x))^3 \sin (c+d x)}{d}+\frac {A \cos (c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{2 d}-\frac {b (15 A b+6 a B-2 b C) (a+b \sec (c+d x))^2 \tan (c+d x)}{6 d}+\frac {1}{6} \int (a+b \sec (c+d x)) \left (3 a \left (12 A b^2+8 a b B+a^2 (A+2 C)\right )+b \left (18 a b B-3 a^2 (A-6 C)+2 b^2 (3 A+2 C)\right ) \sec (c+d x)-2 b \left (18 a A b+6 a^2 B-3 b^2 B-8 a b C\right ) \sec ^2(c+d x)\right ) \, dx\\ &=\frac {(2 A b+a B) (a+b \sec (c+d x))^3 \sin (c+d x)}{d}+\frac {A \cos (c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{2 d}-\frac {b^2 \left (6 a^2 B-3 b^2 B+2 a b (9 A-4 C)\right ) \sec (c+d x) \tan (c+d x)}{6 d}-\frac {b (15 A b+6 a B-2 b C) (a+b \sec (c+d x))^2 \tan (c+d x)}{6 d}+\frac {1}{12} \int \left (6 a^2 \left (12 A b^2+8 a b B+a^2 (A+2 C)\right )+6 b \left (12 a^2 b B+b^3 B+8 a^3 C+4 a b^2 (2 A+C)\right ) \sec (c+d x)-2 b \left (12 a^3 B-24 a b^2 B-2 b^3 (3 A+2 C)+a^2 (39 A b-34 b C)\right ) \sec ^2(c+d x)\right ) \, dx\\ &=\frac {1}{2} a^2 \left (12 A b^2+8 a b B+a^2 (A+2 C)\right ) x+\frac {(2 A b+a B) (a+b \sec (c+d x))^3 \sin (c+d x)}{d}+\frac {A \cos (c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{2 d}-\frac {b^2 \left (6 a^2 B-3 b^2 B+2 a b (9 A-4 C)\right ) \sec (c+d x) \tan (c+d x)}{6 d}-\frac {b (15 A b+6 a B-2 b C) (a+b \sec (c+d x))^2 \tan (c+d x)}{6 d}+\frac {1}{2} \left (b \left (12 a^2 b B+b^3 B+8 a^3 C+4 a b^2 (2 A+C)\right )\right ) \int \sec (c+d x) \, dx-\frac {1}{6} \left (b \left (12 a^3 B-24 a b^2 B+a^2 b (39 A-34 C)-2 b^3 (3 A+2 C)\right )\right ) \int \sec ^2(c+d x) \, dx\\ &=\frac {1}{2} a^2 \left (12 A b^2+8 a b B+a^2 (A+2 C)\right ) x+\frac {b \left (12 a^2 b B+b^3 B+8 a^3 C+4 a b^2 (2 A+C)\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {(2 A b+a B) (a+b \sec (c+d x))^3 \sin (c+d x)}{d}+\frac {A \cos (c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{2 d}-\frac {b^2 \left (6 a^2 B-3 b^2 B+2 a b (9 A-4 C)\right ) \sec (c+d x) \tan (c+d x)}{6 d}-\frac {b (15 A b+6 a B-2 b C) (a+b \sec (c+d x))^2 \tan (c+d x)}{6 d}+\frac {\left (b \left (12 a^3 B-24 a b^2 B+a^2 b (39 A-34 C)-2 b^3 (3 A+2 C)\right )\right ) \text {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{6 d}\\ &=\frac {1}{2} a^2 \left (12 A b^2+8 a b B+a^2 (A+2 C)\right ) x+\frac {b \left (12 a^2 b B+b^3 B+8 a^3 C+4 a b^2 (2 A+C)\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {(2 A b+a B) (a+b \sec (c+d x))^3 \sin (c+d x)}{d}+\frac {A \cos (c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{2 d}-\frac {b \left (12 a^3 B-24 a b^2 B+a^2 b (39 A-34 C)-2 b^3 (3 A+2 C)\right ) \tan (c+d x)}{6 d}-\frac {b^2 \left (6 a^2 B-3 b^2 B+2 a b (9 A-4 C)\right ) \sec (c+d x) \tan (c+d x)}{6 d}-\frac {b (15 A b+6 a B-2 b C) (a+b \sec (c+d x))^2 \tan (c+d x)}{6 d}\\ \end {align*}
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Mathematica [A]
time = 2.40, size = 348, normalized size = 1.27 \begin {gather*} \frac {\sec ^3(c+d x) \left (36 a^2 \left (12 A b^2+8 a b B+a^2 (A+2 C)\right ) (c+d x) \cos (c+d x)+12 a^2 \left (12 A b^2+8 a b B+a^2 (A+2 C)\right ) (c+d x) \cos (3 (c+d x))-48 b \left (12 a^2 b B+b^3 B+8 a^3 C+4 a b^2 (2 A+C)\right ) \cos ^3(c+d x) \left (\log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-\log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )\right )+2 \left (9 a^4 A+24 A b^4+96 a b^3 B+144 a^2 b^2 C+32 b^4 C+12 \left (12 a^3 A b+3 a^4 B+2 b^4 B+8 a b^3 C\right ) \cos (c+d x)+4 \left (3 a^4 A+6 A b^4+24 a b^3 B+36 a^2 b^2 C+4 b^4 C\right ) \cos (2 (c+d x))+48 a^3 A b \cos (3 (c+d x))+12 a^4 B \cos (3 (c+d x))+3 a^4 A \cos (4 (c+d x))\right ) \sin (c+d x)\right )}{96 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.17, size = 295, normalized size = 1.08 Too large to display
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.29, size = 335, normalized size = 1.22 \begin {gather*} \frac {3 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} A a^{4} + 12 \, {\left (d x + c\right )} C a^{4} + 48 \, {\left (d x + c\right )} B a^{3} b + 72 \, {\left (d x + c\right )} A a^{2} b^{2} + 4 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} C b^{4} - 12 \, C a b^{3} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 3 \, B b^{4} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 24 \, C a^{3} b {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 36 \, B a^{2} b^{2} {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 24 \, A a b^{3} {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 12 \, B a^{4} \sin \left (d x + c\right ) + 48 \, A a^{3} b \sin \left (d x + c\right ) + 72 \, C a^{2} b^{2} \tan \left (d x + c\right ) + 48 \, B a b^{3} \tan \left (d x + c\right ) + 12 \, A b^{4} \tan \left (d x + c\right )}{12 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 3.68, size = 269, normalized size = 0.98 \begin {gather*} \frac {6 \, {\left ({\left (A + 2 \, C\right )} a^{4} + 8 \, B a^{3} b + 12 \, A a^{2} b^{2}\right )} d x \cos \left (d x + c\right )^{3} + 3 \, {\left (8 \, C a^{3} b + 12 \, B a^{2} b^{2} + 4 \, {\left (2 \, A + C\right )} a b^{3} + B b^{4}\right )} \cos \left (d x + c\right )^{3} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, {\left (8 \, C a^{3} b + 12 \, B a^{2} b^{2} + 4 \, {\left (2 \, A + C\right )} a b^{3} + B b^{4}\right )} \cos \left (d x + c\right )^{3} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (3 \, A a^{4} \cos \left (d x + c\right )^{4} + 2 \, C b^{4} + 6 \, {\left (B a^{4} + 4 \, A a^{3} b\right )} \cos \left (d x + c\right )^{3} + 2 \, {\left (18 \, C a^{2} b^{2} + 12 \, B a b^{3} + {\left (3 \, A + 2 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{2} + 3 \, {\left (4 \, C a b^{3} + B b^{4}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{12 \, d \cos \left (d x + c\right )^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 550 vs.
\(2 (262) = 524\).
time = 0.57, size = 550, normalized size = 2.01 \begin {gather*} \frac {3 \, {\left (A a^{4} + 2 \, C a^{4} + 8 \, B a^{3} b + 12 \, A a^{2} b^{2}\right )} {\left (d x + c\right )} + 3 \, {\left (8 \, C a^{3} b + 12 \, B a^{2} b^{2} + 8 \, A a b^{3} + 4 \, C a b^{3} + B b^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 3 \, {\left (8 \, C a^{3} b + 12 \, B a^{2} b^{2} + 8 \, A a b^{3} + 4 \, C a b^{3} + B b^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) - \frac {6 \, {\left (A a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 2 \, B a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 8 \, A a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - A a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 2 \, B a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 8 \, A a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{2}} - \frac {2 \, {\left (36 \, C a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 24 \, B a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 12 \, C a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 6 \, A b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 3 \, B b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 6 \, C b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 72 \, C a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 48 \, B a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 12 \, A b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 4 \, C b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 36 \, C a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 24 \, B a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 12 \, C a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 6 \, A b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 3 \, B b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 6 \, C b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{3}}}{6 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 8.94, size = 2500, normalized size = 9.12 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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